This is cool

[Evil3]

I seen this on another forum and thought I would share it with you.

It takes less than a minute.
Work this out as you read ...
Be sure you don't read the bottom until you've worked it out!
This is not one of those waste of time things, its fun.

1. First of all, pick the number of times a week that you would like to go out to eat.
(more than once but less than 10)

2. Multiply this number by 2 (just to be bold)

3. Add 5



4. Multiply it by 50

5. If you have already had your birthday this year add 1756 .
If you haven't, add 1755.


6. Now subtract the four digit year that you were born.


You should have a three digit number


The first digit of this was your original number
(I.e., how! Many times you want to go out to restaurants in a week.)

The next two numbers are

YOUR AGE! (Oh YES, it is!!!!!)

THIS IS THE ONLY YEAR (2006) IT WILL EVER WORK, SO SPREAD IT AROUND WHILE IT LASTS

enjoy

[Traxxas_Junkee]

thats awesome!

[Czech-it-Out Graphics]

it was on the grid

[Czech-it-Out Graphics]

he says its really quite simple but i disagree lol

#1255 by Erik Elliott (killer87) on Thu Oct 26 23:41:56 EDT 2006:

its really quite simple. You basically need the 1st number you pick
multiplied by 100. Then you add a random number to that. Then have
people add a number to get it such that the total becomes 2006 for
people who already had their birthday and 2005 for those who havent.
Then, when you subtract your birth year, you get your age plus the
original number times 100.

ex:

x is the number you picked from 1-10.

Multiply by 20. ( 20x )

Add 69 (20x + 69)

Multiply by 5 (100x + 345) (See how the original number x has now been
mutiplied by 100?)

Add 1661 if you've had your birthday, 1660 if not. (notice how 345+1661
= 2006 and 345+1660 = 2005. These are the years of your last
birthday. So you get 100x+2006 and 100x+2005.)

Now subtract the year you were born. (you will get your age + 100x.
This results in the original number x being in the hundreds spot (1st
number) and your age next.)


Just math...