Help....

[Ponch]

LMK if you have even the slighest idea on what to do (next, besides burn/throw away etc) on any of these problems.



Thanks,
Ponch aka Matt

[DAVEC-NITRO-RS4]

Mike.....

[motoxer4life]

wow thats confusing dude. good luck!

[nitrodude]

Are you trying to confuse people?
I know you already confused me! :confused:
lol
I want to see someone figure this out!

[DAVEC-NITRO-RS4]

Not too difficult really.

[Ponch]

Ok WELP I got 1 done. The last one. Since AFCE is a rhombus, all sides are the same length. so FC is also 16-x, and BC is 12 (it's a given). So you use the pythagorean thm. and the eq. is the square root of (16-x)(16-x)-144 which equals 32x=112 you divide 112 by 32 and get 3.5. So x is 3.5. Then, you use the pythagorean thm again (now you know the sides of the rhombus are all 12.5) to find EF. the equation is 12.5x12.5+12.5x12.5 and that ='s 312.5. Then you find the sq. root of that, which is about 17.67. <---that's the answer.

[nitrodude]

Totally lost! :confused: :confused: :confused: :confused: :confused:

[nitrodude]

Not too difficult really.

If its not dificult why havent you figured it out yet?
lol

[Ponch]

Guys, in problem #3 (kite looking one), anyone know how to get the length of BP and QD??? I can solve the rest from there...

[DAVEC-NITRO-RS4]

#1 - PQ is 12- sq.rt of 85...roughly 2.78

[nitrodude]

Ponch is this your math homwork and your trying to get other people to do it for you???
LOL

[DAVEC-NITRO-RS4]

#3 - ABC is a right triangle (3-4-5 relatonship) take it from there.

[motoxer4life]

Ok WELP I got 1 done. The last one. Since AFCE is a rhombus, all sides are the same length. so FC is also 16-x, and BC is 12 (it's a given). So you use the pythagorean thm. and the eq. is the square root of (16-x)(16-x)-144 which equals 32x=112 you divide 112 by 32 and get 3.5. So x is 3.5. Then, you use the pythagorean thm again (now you know the sides of the rhombus are all 12.5) to find EF. the equation is 12.5x12.5+12.5x12.5 and that ='s 312.5. Then you find the sq. root of that, which is about 17.67. <---that's the answer.

WOW. i think ill go and kill myself before i have to do that stuff.

[Ponch]

Dave not sure how you got the answer to #1, care to elaborate?

And I see that it's a 3-4-5 triangle, not sure where to go from there but I'll look at it for a while.

[Ponch]

Oh duh...345 means it's a right triangle duh...

[rocco79]

Yeah where mike? Hes soooooooooooooooooooooooooooooooooooooooooo smart

[Ponch]

#1 - PQ is 12- sq.rt of 85...roughly 2.78

I'm a little confused. PQ is 12 minus the sq.rt of 85?

root 85 is 9.219544457 12-rt 85 equals 2.78

But there's no way in hell that PQ can be 2.78. Since PQ,PD, and PA are congruent, the PA and PD would also be 2.78. That won't work, because in any given triangle, any 2 sides must add up to a number greater than the third side, but 2.78x2= 5.56

5.56 is not > 12

[DAVEC-NITRO-RS4]

I got EF = 15 for #3.

[Ponch]

I got EF = 15 for #3.

Eek. Care to share how...?

[DAVEC-NITRO-RS4]

Tutoring comes extra.

[Ponch]

http://www.mathopenref.com/heronsformula.html

Great page. I solved the kite one with it, got 3 for PQ.

[Ponch]

Tutoring comes extra.

doh!

haha. Welp thanks for the help guys, I got the 2 I needed solved.

[nitrodude]

Was that home work or what?

[motoxer4life]

Was that home work or what?

no im sure he just loves to practice math in his spare time.....








OF COURSE ITS HOMEWORK!!! lol

[rocco79]

No...
Matt love to solve complex math/geometry problems as a hobby. Its somthing he likes to do on rainy sundays...

Heres your sign.